公轉自轉旅行的角速度，單位是每小時幾圈， ω 1,ω 2,ω 3\omega_1, \omega_2, \omega_3 。旅行的角速度相對於自轉定義。一開始陽光射線…角度是0，時間 tt 的時候相對於陽光射線的角度是 (ω 2+ω 3−ω 1)t(\omega_2 + \omega_3 - \omega_1) t
ω 1(24×365)=1 (ω 2−ω 1)24×365=365 ω 1=124×365 ω 2=36624×365 (ω 2−ω 1)t=79 t=24×79 (ω 2+ω 3−ω 1)t=80 ω 3=124×79\begin{aligned}\omega_1 ( 24 \times 365 ) = 1\\(\omega_2 - \omega_1) 24 \times 365 = 365\\\omega_1 = \frac{1}{24 \times 365}\\\omega_2 = \frac{366}{24 \times 365}\\(\omega_2 - \omega_1)t = 79\\t = 24 \times 79\\(\omega_2 + \omega_3 - \omega_1) t = 80\\\omega_3 = \frac{1}{24 \times 79}\end{aligned}
